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Another math problem [OTHER]
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Nygen Dale
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Registered: 21.Jun.03
Write new replyThu 08 Dec. 2005 (9:44) [212.65.19.122] 51/53 quick link
kazakore wrote on 07 Dec. (22:30) :

My guess would be 11100001


225 in binary :p


At first I also thought it had something to do with that but it doesn't :p

MatthijsB wrote on 08 Dec. (0:37) :

think the answer is none, I went up into millions and saw that every value that came close had 25 too much each time :(


Yeah, it does go up to millions but there is a solution :excited:

Hint: 225 = 9 * 25 :idea:
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kazakore
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Write new replyThu 08 Dec. 2005 (16:41) [213.52.138.34] 52/53 quick link
is it 11111111100 or is there a lower one?


My reasoning:

Well it's got to end in a 00, being a multiple of 225 and needing to be only 1s and 0s, so to end in one 0 will always end 50.

225 is a bitch of a number to work with, multiply by 4 to give 900, the first number to end in 00. You can also deduce that any other number ending in 00 is going to be devisable by 900.

This give the magic number 9, where you should of learn in school that all numbers that are devidable by 9 all the digits add up to 9. This means our number is going to have to have nine 1s.

Nine 1s and chuck the two 0s we worked out earlier you are going to need and you get 11111111100



So anybody got a lower one?


Sorry no real maths. More of a visual pattern type person ;)
Infexious: The Definitive Electronic Music Community (231 hits)
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Nygen Dale
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Registered: 21.Jun.03
Write new replyThu 08 Dec. 2005 (16:54) [212.65.19.122] 53/53 quick link
kazakore wrote on 08 Dec. (16:41) :

is it 11111111100 or is there a lower one?


My reasoning:

Well it's got to end in a 00, being a multiple of 225 and needing to be only 1s and 0s, so to end in one 0 will always end 50.

225 is a bitch of a number to work with, multiply by 4 to give 900, the first number to end in 00. You can also deduce that any other number ending in 00 is going to be devisable by 900.

This give the magic number 9, where you should of learn in school that all numbers that are devidable by 9 all the digits add up to 9. This means our number is going to have to have nine 1s.

Nine 1s and chuck the two 0s we worked out earlier you are going to need and you get 11111111100



So anybody got a lower one?


Sorry no real maths. More of a visual pattern type person ;)


Don't be sorry, that's exactly the kinda solution we were looking for :bravo:
We have a winner! :gift:
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